Ok, time to break out my gift of Math dork-dum....
The vette is traveling at a rate of 293.33ft/sec, with zero change in acceleration...
The drag car has a rate of change from 0 to 333mph in the time of 4.441, with some converting, the drag car accelerates at the rate of 109.98 ft/sec*sec. (this is found by a = (Vf - Vi)/T, or 488.4 ft/sec / 4.441 secs.
Now comes the fun part.. The equations.
Here is the equation for the Vette
Xc = Xo + VoT
Equation for the Drag car is
Xd = Xo + Vo + 1/2at^2
Set Xc = Xd = x and find T
From the first equation, T = x/Vc, then substitute that into the 2nd equation
x = 1/2a(x/Vc)^2
Solve for x and you get x = 2Vc^2/a = 2(293.33)^2 / 109.98 = 1564.69 ft.. The vette can never lose, must have been a Z06.
(should be right unless I screwed up a conversion)
Edit.. this is correct... BUT only if the drag car has the SAME acceleration rate for the whole 4.441 secs which is false.