Jump to content

statistics Q...


magley64

Recommended Posts

now ur suggesting the probability of picking a card marked X which becomes 16/52

now lets do this, put an x on all diamonds, what is the probability of picking card marked x = 13/52

now put a Y on all aces probability is 4/52

what is the probability that of picking either x or y ... i pick back to back 16 x put it back then back to back 4 y then it is 17, the condition never excluded a thing with both x and y.

\

Edit

By far the most hated class I have ever had to take.

Link to comment
Share on other sites

The answer is def. 16/52

Doc, try to use your logic to answer this slight modification: what are the odds of drawing a red suit, a diamond, or a heart? Clearly there are overlapping sets here, but you cannot say that 26/52(red) + 13/52(diamond) + 13/52(heart) = 52/52, otherwise you would have a 100% probability of drawing a red suit, diamond or a heart. You have to reduce cards that are included twice.

Link to comment
Share on other sites

The answer is def. 16/52

Doc, try to use your logic to answer this slight modification: what are the odds of drawing a red suit, a diamond, or a heart? Clearly there are overlapping sets here, but you cannot say that 26/52(red) + 13/52(diamond) + 13/52(heart) = 52/52, otherwise you would have a 100% probability of drawing a red suit, diamond or a heart. You have to reduce cards that are included twice.

in your example the criteria is red, there is no confusion there,

ie a card which is red which can be either diamond or heart

Card >> RED ( 1 probability) >> diamond or heart

but the question above there is one card which satisfies both criteria, but are mutually exclusive.

here a card which is either ace or diamond.

Card>> ace (1 probability) or diamond (1 probability)

Then again i am just stating a different point of view, am not saying i am right.

Link to comment
Share on other sites

may be i am basing my argument more on psycho-philosophical base rather than maths :(

i mean i am setting this argument from the observer basis saying that he is ignoring the fact that ace of diamond that he drew twice is one and the same card.

Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...