xxxShaftxxx Posted November 5, 2004 Report Share Posted November 5, 2004 I missed the lecture on this section and I'm having trouble understanding what to do. Does anyone here know how to rewrite a logarithmic expression into a single expression? For instance ln (e^2) = 2lne I have two problems in which I do not understand.. Can someone help me out? 1.)ln(e^2x) + ln(ey) - 3 My answer 3lne + lnx + lny - 3 _____________________________ 2.) ln (square root(x^2y) / cube root(y) My answer = (1/2) (2lnx) (lny) - (1/3(lny)) Quote Link to comment Share on other sites More sharing options...
grease monkey Posted November 5, 2004 Report Share Posted November 5, 2004 uuuhh, 2? graemlins/wtf.gif Quote Link to comment Share on other sites More sharing options...
Berto Posted November 5, 2004 Report Share Posted November 5, 2004 the problem i notice is that your answer's don't have equal signs, what section in your book are you covering? Quote Link to comment Share on other sites More sharing options...
JaSSon Posted November 5, 2004 Report Share Posted November 5, 2004 OH man, i covered this crap last quarter,, i should be able to remember this. Quote Link to comment Share on other sites More sharing options...
pg Posted November 5, 2004 Report Share Posted November 5, 2004 Ask B Dubs he is the math genius he helps me with my calculus. But uh I don't know where you got some of your answers so I would ask Brandon he should know. smile.gif Quote Link to comment Share on other sites More sharing options...
supldys Posted November 5, 2004 Report Share Posted November 5, 2004 actually i learned that stuff in high school, and a little more in college, but would you believe i cant remember haha Quote Link to comment Share on other sites More sharing options...
Guest doggunracing Posted November 5, 2004 Report Share Posted November 5, 2004 Originally posted by Atmosphere: I missed the lecture on this section and I'm having trouble understanding what to do. Does anyone here know how to rewrite a logarithmic expression into a single expression? For instance ln (e^2) = 2lne I have two problems in which I do not understand.. Can someone help me out? 1.)ln(e^2x) + ln(ey) - 3 My answer 3lne + lnx + lny - 3 _____________________________ 2.) ln (square root(x^2y) / cube root(y) My answer = (1/2) (2lnx) (lny) - (1/3(lny))Well, ln(e) is 1. So, 2*ln(e) is just 2. So, ln(e^2x) + ln(ey) - 3, is just 2x+y-3. ln (square root(x^2y) / cube root(y)) First, solve the inside. You were missing a parenthesis, so I'm going on my changed version above. ln (x^y / y^(1/3)). x^2y is just (x^2)^y, so the sqrt of it is just x^y. So, y*ln(x) - (1/3)ln(y) Originally posted by RX7dood: the problem i notice is that your answer's don't have equal signs, what section in your book are you covering?They're just rewritings, not equations. Quote Link to comment Share on other sites More sharing options...
black00ws6 Posted November 5, 2004 Report Share Posted November 5, 2004 College math? I had this stuff in the 8-9th grade.. But my dork ass majored in math too. Quote Link to comment Share on other sites More sharing options...
xxxShaftxxx Posted November 6, 2004 Author Report Share Posted November 6, 2004 It's Math 148 at OSU. Quote Link to comment Share on other sites More sharing options...
AngryBMW Posted November 6, 2004 Report Share Posted November 6, 2004 Originally posted by Atmosphere: It's Math 148 at OSU.Jesus...I took that class spring quarter and I already forgot how to do it. -Marc Quote Link to comment Share on other sites More sharing options...
Tulo Posted November 6, 2004 Report Share Posted November 6, 2004 Originally posted by Atmosphere: It's Math 148 at OSU. Do you have Andrews as your lecturer? Quote Link to comment Share on other sites More sharing options...
black00ws6 Posted November 6, 2004 Report Share Posted November 6, 2004 I started at math 151 and took about 20 math classes after that. But I started back in 94... damn I'm old Quote Link to comment Share on other sites More sharing options...
xxxShaftxxx Posted November 7, 2004 Author Report Share Posted November 7, 2004 I have an Indian Lady that doesn't speak very good English.. Her name is Angelica. Quote Link to comment Share on other sites More sharing options...
Science Abuse Posted November 7, 2004 Report Share Posted November 7, 2004 the answer, my freind, is blowing in the wind. Quote Link to comment Share on other sites More sharing options...
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