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College Math homework problem


xxxShaftxxx

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I missed the lecture on this section and I'm having trouble understanding what to do. Does anyone here know how to rewrite a logarithmic expression into a single expression? For instance

 

ln (e^2) = 2lne

 

I have two problems in which I do not understand.. Can someone help me out?

 

1.)ln(e^2x) + ln(ey) - 3

 

My answer

 

3lne + lnx + lny - 3

 

_____________________________

 

2.) ln (square root(x^2y) / cube root(y)

 

My answer =

 

(1/2) (2lnx) (lny) - (1/3(lny))

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Guest doggunracing
Originally posted by Atmosphere:

I missed the lecture on this section and I'm having trouble understanding what to do. Does anyone here know how to rewrite a logarithmic expression into a single expression? For instance

 

ln (e^2) = 2lne

 

I have two problems in which I do not understand.. Can someone help me out?

 

1.)ln(e^2x) + ln(ey) - 3

 

My answer

 

3lne + lnx + lny - 3

 

_____________________________

 

2.) ln (square root(x^2y) / cube root(y)

 

My answer =

 

(1/2) (2lnx) (lny) - (1/3(lny))

Well, ln(e) is 1. So, 2*ln(e) is just 2.

 

So, ln(e^2x) + ln(ey) - 3, is just 2x+y-3.

 

ln (square root(x^2y) / cube root(y))

First, solve the inside. You were missing a parenthesis, so I'm going on my changed version above.

ln (x^y / y^(1/3)). x^2y is just (x^2)^y, so the sqrt of it is just x^y.

So, y*ln(x) - (1/3)ln(y)

 

Originally posted by RX7dood:

the problem i notice is that your answer's don't have equal signs, what section in your book are you covering?

They're just rewritings, not equations.
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