Need help: math question

[Ramsey]

So i have a cylinder with a 236" diameter.

 

 

 

I cut it at 28.75 degrees.

 

 

 

How can i find the dimensions of the oval surface it creates?

 

tia

 

this may help: i just cant seem to figure it out.

 

area of an ellipse is given by Pi*a*b, where 2*a is the length of the

longer side (measured at its greatest width) and 2*b is the length of

the shortest side (measured at its greatest height).

 

edit: I have the long dist of the plane at 269 3/16"

[Ramsey]

is this right?

(Pi x r^2)/cos(theta)

(3.14 x 168^2) / cos(28.75) = 101135.628 square inches

[99FLHRCI]

If you picture the cylinder from the side, the area cut off would create a right triangle with side b being 236", angle A being 28.75 and angle C being 90. Using the calculator below:

 

http://www.cleavebooks.co.uk/scol/calrtri.htm

 

You can get side c as being 269". Now you know the ellipse has a minor axis of 236" and a major axis of 269". Using the calculator below:

 

http://www.cleavebooks.co.uk/scol/callipse.htm

 

You come to the conclusion that the area of the resulting ellipse is 49,900 sq. in.

 

Hope this helps. I do not remember all of the formulas to do this but I once had a teacher that made sure to point out that a smart man doesn't have all the answers he just knows where to find them.

[87GT]

The answer is 42 you n00bs.

[black00ws6]

pi (r^2)/cos 28.5

 

 

Just saw your 2nd post.. formula looks right, but where did 168 come from?

[Ramsey]

pi (r^2)/cos 28.5

 

 

Just saw your 2nd post.. formula looks right, but where did 168 come from?

 

idk... that was an ot answer