Brandon Posted July 29, 2008 Author Report Share Posted July 29, 2008 Have to respect a man that owns a near 700whp car and still has a sense of humor. Edit - YIKES, using a 'FCU' and re-labeled split second piggy back on the price tag of 8-9 grand? That is paxtons' doing Quote Link to comment Share on other sites More sharing options...
RedRocket1647545505 Posted July 29, 2008 Report Share Posted July 29, 2008 Wouldn't the X scale "move" in relation to the Y scales then? Shouldn't the X scale 5252 move along with where HP/TQ cross, no matter how the Y scales are scaled? That's what I meant by X scale shouldn't be affected, as that point should move in relation to where it crosses, no matter what the Yscales. Huh? Here's what I'm saying in picture form. They 'cross', just not on this graph, due to the way it's plotted. http://i38.tinypic.com/14wqc5i.jpg Quote Link to comment Share on other sites More sharing options...
RangerTurbo Posted July 29, 2008 Report Share Posted July 29, 2008 EDITED: I see what you mean now. Disregard the rest. I was confusing maxHP and maxTQ with what takes place at 5252. But, If there are two different Yscales, it's going to affect where the physical location of the "cross" point on the graph will be. Now, knowing that, the Xscale will shift, and scale itself to show 5252 directly below the cross point, no? You say that at 5252rpm, the car makes 600HP/600TQ. That doesn't seem logical. That would mean every car every dynoed would be 600/600, or 500/500, or 601/601 when it crossed at 5252rpm. That simply isn't what happens though. I'm just trying to understand the graph is all. Quote Link to comment Share on other sites More sharing options...
Mallard Posted July 29, 2008 Report Share Posted July 29, 2008 Um...that's exactly what happens at 5252. Hp=Torque at 5252 rpm. You can graph it to look any way that you want. Quote Link to comment Share on other sites More sharing options...
RangerTurbo Posted July 29, 2008 Report Share Posted July 29, 2008 5252. Hp=Torque at 5252 rpm. That was my oversight. Thanks. Quote Link to comment Share on other sites More sharing options...
RedRocket1647545505 Posted July 29, 2008 Report Share Posted July 29, 2008 Mallard said it better than I could. HP is a factor of TQ. IIRC, dynos measure torque, and calculate HP from that. HP = TQ x RPM / 5252 Now, I can't remember exactly why the magical number is 5252, but I Googled it at some point, but have forgotten since. HP and TQ are always the same at 5252. Always. Quote Link to comment Share on other sites More sharing options...
TimTheAzn Posted July 30, 2008 Report Share Posted July 30, 2008 nice viper Quote Link to comment Share on other sites More sharing options...
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